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[v0.98][Refactoring] Use int for peak performance, which makes code cleaner

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Dr-Noob
2021-08-06 11:04:29 +02:00
parent 6953d8dda5
commit c24dd7cbb6
9 changed files with 106 additions and 115 deletions
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87
src/x86/cpuid.c
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@@ -133,6 +133,49 @@ struct uarch* get_cpu_uarch(struct cpuInfo* cpu) {
return get_uarch_from_cpuid(cpu, efamily, family, emodel, model, (int)stepping);
}
int64_t get_peak_performance(struct cpuInfo* cpu, struct topology* topo, int64_t freq) {
/*
* PP = PeakPerformance
* SP = SinglePrecision
*
* PP(SP) =
* N_CORES *
* FREQUENCY *
* 2(Two vector units) *
* 2(If cpu has fma) *
* 16(If AVX512), 8(If AVX), 4(If SSE) *
*/
//First, check we have consistent data
if(freq == UNKNOWN_FREQ) {
return -1;
}
struct features* feat = cpu->feat;
int vpus = get_number_of_vpus(cpu);
int64_t flops = topo->physical_cores * topo->sockets * (freq*1000000) * vpus;
if(feat->FMA3 || feat->FMA4)
flops = flops*2;
// Ice Lake has AVX512, but it has 1 VPU for AVX512, while
// it has 2 for AVX2. If this is a Ice Lake CPU, we are computing
// the peak performance supposing AVX2, not AVX512
if(feat->AVX512 && vpus_are_AVX512(cpu))
flops = flops*16;
else if(feat->AVX || feat->AVX2)
flops = flops*8;
else if(feat->SSE)
flops = flops*4;
// See https://sites.utexas.edu/jdm4372/2018/01/22/a-peculiar-
// throughput-limitation-on-intels-xeon-phi-x200-knights-landing/
if(is_knights_landing(cpu))
flops = flops * 6 / 7;
return flops;
}
struct hypervisor* get_hp_info(bool hv_present) {
struct hypervisor* hv = emalloc(sizeof(struct hypervisor));
if(!hv_present) {
@@ -289,6 +332,7 @@ struct cpuInfo* get_cpu_info() {
cpu->freq = get_frequency_info(cpu);
cpu->cach = get_cache_info(cpu);
cpu->topo = get_topology_info(cpu, cpu->cach);
cpu->peak_performance = get_peak_performance(cpu, cpu->topo, get_freq(cpu->freq));
if(cpu->cach == NULL || cpu->topo == NULL) {
return NULL;
@@ -656,49 +700,6 @@ struct frequency* get_frequency_info(struct cpuInfo* cpu) {
}
// STRING FUNCTIONS
bool get_peak_performance(struct cpuInfo* cpu, struct topology* topo, int64_t freq, double* flops) {
/*
* PP = PeakPerformance
* SP = SinglePrecision
*
* PP(SP) =
* N_CORES *
* FREQUENCY *
* 2(Two vector units) *
* 2(If cpu has fma) *
* 16(If AVX512), 8(If AVX), 4(If SSE) *
*/
//First, check we have consistent data
if(freq == UNKNOWN_FREQ) {
return false;
}
struct features* feat = cpu->feat;
int vpus = get_number_of_vpus(cpu);
*flops = topo->physical_cores * topo->sockets * (freq*1000000) * vpus;
if(feat->FMA3 || feat->FMA4)
*flops = *flops*2;
// Ice Lake has AVX512, but it has 1 VPU for AVX512, while
// it has 2 for AVX2. If this is a Ice Lake CPU, we are computing
// the peak performance supposing AVX2, not AVX512
if(feat->AVX512 && vpus_are_AVX512(cpu))
*flops = *flops*16;
else if(feat->AVX || feat->AVX2)
*flops = *flops*8;
else if(feat->SSE)
*flops = *flops*4;
// See https://sites.utexas.edu/jdm4372/2018/01/22/a-peculiar-
// throughput-limitation-on-intels-xeon-phi-x200-knights-landing/
if(is_knights_landing(cpu))
*flops = *flops * 6 / 7;
return true;
}
// TODO: Refactoring
char* get_str_topology(struct cpuInfo* cpu, struct topology* topo, bool dual_socket) {
char* string;

2
src/x86/cpuid.h
View File

@@ -13,8 +13,6 @@ char* get_str_sse(struct cpuInfo* cpu);
char* get_str_fma(struct cpuInfo* cpu);
char* get_str_topology(struct cpuInfo* cpu, struct topology* topo, bool dual_socket);
bool get_peak_performance(struct cpuInfo* cpu, struct topology* topo, int64_t freq, double* flops);
void print_debug(struct cpuInfo* cpu);
void print_raw(struct cpuInfo* cpu);